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2 hobo
try fighting a monster and an archangel one-on-one, and you'll see that the monster almost always wins. That difference of 2 in stats and the 50 HP buffer probably make the difference ;-)
Battle 1: 1 Archangel vs. 1 Ancient Behemoth.
Assumptions:
1) Neither side gets a lucky break (damage boost) during the battle.
2) Neither side gets a morale boost (extra turn or skipped turn) during the battle.
Since the archangel has +1 to morale, the second assumption favors the Ancient Behemoth in the calculation.
Damage dealt by the archangel per hit: 50 (base) + 11 (difference between the archangel's attack and the Ancient Behemoth's defense) * 2.5 (5% of the base damage of 50 HP, for a 1-attack advantage) = 77.5. Rounding down, we get 77.
Damage dealt by the Ancient Behemoth per hit: 50 (base, taking the maximum, although it could be less) + 13 (difference between the Ancient Behemoth's attack and the archangel's defense, taking into account the archangel's 80% defense reduction) * 2.5 (5% of the base damage of 50 HP, for a 1-attack advantage) = 82.5. Rounding up (I rounded down for the archangel!!!), we get 83.
Turn 1: The archangel waits. The Ancient Behemoth either moves to maximum range (or to a non-maximum range, or skips its turn, which doesn't matter). The archangel hits for 77 HP, and the Ancient Behemoth retaliates for 83 (Archangel: 167 HP, Ancient Behemoth: 223).
Turn 2: The archangel hits for 77 HP, and the Ancient Behemoth retaliates for 83 (Archangel: 84 HP, Ancient Behemoth: 146). The Ancient Behemoth hits for 83, and the archangel retaliates for 77 (Archangel: 1 HP, Ancient Behemoth: 69).
Turn 3: The archangel hits for 77 HP, killing the Ancient Behemoth.
As you can see, even in the best-case scenario for the Ancient Behemoth, the archangel wins.
Or did I make a mistake in the calculation?

