b^4 - 7056b^2 + 7056 = 0;
Basically, we need to solve this biquadratic equation, find b, then use the Pythagorean theorem to find a, and then find the area.
И пока в кармане пачка милкиуэйев - значит все не так уж плохо на сегодняшний день
New here? I'm Roha — want a quick tour?
By the way, did Nebk have a holiday yesterday, or am I mistaken?
Okay, let's write it down:
b^4-7056b^2+7056=0;
Basically, we need to solve this biquadratic equation, find b, then use the Pythagorean theorem to find a, and then find the area.
No. Where did you get that from?
Are you someone's clone?
We have a right triangle. Its hypotenuse is 12, and the altitude to the hypotenuse is 7. What is its area?

Mort, look what I found.
the PUT side = hypotenuse divided by the square root of 2
What is this? :smile28:
Where did this formula even come from?

This is a solution to a system of equations based on well-known formulas after simplifying like terms.

42
This is a good answer, but not to my question, but to some other question.

I think Ment is just using all his strategic reserves for his thesis (or whatever he's writing). And the puzzles are just... a way to distract himself and have some fun.