Well, half a millimeter, if going deeper, and if the deepest point is the middle of the capacitor.
A more obvious riddle: "How deep into the forest can a deer run?"
Hermit, please, ask the next riddle.
The force that will slow down the electron: F = 3.8 * 10-6 * 1.6 * 10-19 = 6.08 * 10-25 N
The deceleration will be: a = F/m = 6.08 * 10-25 / 9 * 10-31 = (6.08/9) * 106 m/s2
And then we'll calculate the distance: s = v2 / (2a) = 1002 / (2 * (6.08/9) * 106) = 104 / (106 * 2 * 6.08/9) = 9 / (100 * 2 * 6.08) = 9 / 1216 = 0.0074013157895 m