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How is the damage from "Wrath of the Gods" calculated in the game? The manual doesn't explain it clearly.
For example, I tested it in a duel between Helmar and Iris, systematically using 40 griffins. I defeated Helmar, eliminating 200 warriors, 30 priests, 75 harpooners, 2 dragons, and 6 thanes. In the end, Helmar could only destroy 33 griffins.
Damage = 3 * (Sorcery + 7) * R
R = sqrt(200 * 1 + 30 * 5 + 75 * 2 + 2 * 7 + 6 + 6) = sqrt(550), so
Damage = 3 * (Sorcery + 7) * sqrt(550) = 1196
(sqrt - square root)
If a griffin has 35 + 2 (Iris has Endurance) = 37 HP, then it takes 32-33 griffins per cast.
For example: if I have 20 sorcery, and I defeat 2000 warriors, how much damage will I deal to the target?
On Expert = 4 * 27 * sqrt(2000) = 4829