[HMM II TOURNAMENT OFF] The second stage of the Van Cunningham 2008 tournament.

It's a bit strange that this battle is causing questions. First with Kamikaze, now with you... I'll explain in detail. Starting disposition: centaurs-goblins-1 gargoyle-6 gargoyles-orcs. The task is simple: to defeat the minotaurs and griffins with minimal losses, and we'll deal with the hydras later. Round 1: 1 Gargoyle takes revenge on the minotaurs, the rest attack the enemy centaurs and finish them off in retaliation. Meanwhile, the orcs die from the griffins and gargoyles without even getting a turn. Fortunately, we attack the minotaurs with goblins, and the centaurs shoot at them. Round 2: The gargoyles retreat, and the enemy griffins and gargoyles attack them. The minotaurs kill the centaurs, but then the already weakened goblins send them and the minotaurs to their ancestors. Round 3: Fortunately, we attack the griffins with goblins. Round 4: We finish off the griffins; the gargoyles are already killed by the goblins' retaliation. Then the most interesting part begins: the goblins put the principle "they won't catch us" into practice, because the warlock quickly curses the main (and still almost unharmed in battle) goblin squad, and Благо attacks the 5 hydras. This situation is not in our favor. The long-distance race continues until the enemy runs out of mana and the spells expire. Next, we implement the principle "the main thing is to defeat them, and then we'll finish them off." Благо (the third and last of our arsenal) attacks the goblins, and then we use auto-battle. 2Catch

To be honest, I didn't believe that the yellow one could be killed in the first week, so I didn't even consider a result of seven days.

Although HW is a young resource, it already has its own traditions. One has already been mentioned: the saves of the winners are presented to the public in full. Another is that if it seems that a map can be completed in 8-9 days, then it will be completed in 7, sometimes even by several people. It's almost a magical number.