Tactical techniques for conducting battles in Heroes of Might and Magic II.

Oh, we're getting carried away ;)
1. The hero gets 6-10 centaurs (on average 8), so from 4 heroes, there are 32 in total!
2. Centaurs deal 1-2 damage, on average 1.5! But a centaur has 3 attacks, and an elemental has about 8 defense! So, the damage will be barely 1 elemental - or even less, somewhere around 35 damage.
So, even if there are only 20 elementals, and we also have 10-12 gargoyles against the centaurs, then at best, about 10 elementals can be defeated! :)

Captain is right, - Alex_R, remember your own walkthrough or vbn's from the seventh stage of the Van Canningham tournament.
The attack will most likely be done by a Barbarian, so the difference in attack and defense will be minimized. The remaining elementals can be finished off with goblins.

2 Kenshido
Is this your only nickname? Is the legendary Himuro Kenshin not a relative?

2 снайп
If the nearest units are 1 peasant and 1 swordsman, then any unit except witches will attack the swordsman. I haven't researched the behavior of witches.