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In reply to Ment
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#476
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No, I still don't know English. This number won't help me. We need to look at it from a different perspective.
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#477
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This is Uranus.
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#478
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If anything, regarding the meaning – it's about the 26 letters of the alphabet. And in general, if you don't Google the answer to the question, then... why not use Google? For example, to find suitable letters... I can't forbid it. And yes, 15 letters. Otherwise, it's unclear what to aim for, which is bad.
 

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#479
uncopyrightable
С уважением, Дубинкин.
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#482
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Meanwhile, I figured out why the bug will eventually reach the end. :D To do this, I had to change the bug's speed reduction to an alternative setting.

Ничто не возникает из ничего и ничто не пропадает бесследно.
Если где-то чего-то убудет, то в другом месте добавится.

(Закон сохранения).

In reply to Злобный Ящур
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#483
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Evil Lizard
Yeah, right. In that time, the bug will crawl 1.6*10^43 cm. And the wick will lengthen by 1.6*10^43 m. And where is the end???:confused:

It will crawl as much as you wrote, and the wick will lengthen as much as you wrote, but the wick in front of it will increase by 1.6*10^43 - 99 centimeters, that is, by as much as it crawled minus 99 centimeters. :D
Всё не так плохо как Вы думаете. Всё намного хуже!
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#484
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I just have a simple question.
Uran, by the way, would you prefer to be called Uran or Uranium? Russian or Latin? ))
 

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In reply to Ment
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#485
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It makes absolutely no difference. Even if it were the one hundred and thirty-fifth.
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#486
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Uranus.
А, вот почему.

🏹🎪+⛓️♿=💕
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#487
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I can’t think of anything. Someone, please suggest something out of turn.
С уважением, Дубинкин.
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#488
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An electron with a speed of 100 m/s enters a capacitor through a hole in the negative plate.
The electric field strength in the capacitor is 3.8*10^(-6) N/C.
The distance between the plates is 1 mm.
The electron has a mass of approximately 9*10^(-31) kg and a charge of 1.6*10^(-19) C.
How far into the capacitor can the electron penetrate?
 

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#489
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Will it pierce through, right?
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#491
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I don't remember the formula and I won't Google it. I'll answer this way: if it entered with a negative value, it will reach the positive value.