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Judging by the "Favorites" table, you'll have to eliminate at least half, maybe 10-15 people :D, or the tables just haven't been updated? :confused:
either a qualifying round of 1/64, the essence doesn't change much.
So far, five people have not used their championship rights:
1. Ayauhteotl - champion of tournament m200 No. 6.
2. Pit for LM - champion of the SOD tournament held in Moscow in the spring of 2013.
3. Champion of the Diamond Monsters tournament - we are waiting for the winner.
4. vysokiy - champion of the novice tournament, winter 2013.
5. AlexTheGreat - champion of the only XL tournament.
In 1/32, 1/64, this is a tournament stage with 128 players.
There are 10 vacant spots left, and at least 5 can be announced.
Also, it's interesting to know what principle will be used to select players for seeded/unseeded positions. In my opinion, will it be based on personal assessment/rating/blind draw?
P.S. Sorry if this curiosity is annoying.
it's obviously a typo; it meant a bracket for 1/128, i.e., an increase in qualification by 1 round.
The selection principle has already been answered more than once, even three times; you can find detailed answers to this question on the next page.
In short, it's based on rating + all merits/achievements in the SOD.
Round 1/128 implies 128 pairs; the number after the fraction indicates the number of pairs, not the number of participants (e.g., in 1/2, 4 teams play, not 2).
I was asking about the qualifying round; everything is written and clear about the groups.
There are 10 vacant spots left; at least 5 can be announced.
And it's interesting to know what principle will be used to select players for seeded/unseeded positions. Based on personal opinion/rating/blind draw?
MINI-CONTESTS