One for all and all for one 5

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So, you should have kept the explanation consistent with the provided quote. The point is that with an even number of participants, the captains are in equal conditions: the "last captain" (A) picks first in two rounds, and the "first captain" (B) picks first in only one round. Therefore, in a draft with 4 players per team, the captain who receives fewer votes should theoretically face the following situation: Player 1: B > A Player 2: A > B Player 3: B > A Player 4: A > B This looks more balanced than if you add another participant to the draft.

Now, pay close attention. By reducing the number of participants in one pool, we equalize the strength of the pools. I can name 16 players who are approximately equal in strength for the captain slot. Now look. We have 16 captains of equal strength (the difference in skill is minimal). Now, we repeat your scheme, and we will see that captain 1 will pick first twice and last twice, and captain 16 will pick first twice and last twice. At the same time, the team compositions in the pools will be more equal due to the reduced variance

Когда рестартов не осталось, обязательно ждите Гурниссона без балисты:D

Комплимент который сделал мой день:
Катя ЭПИК барышня) вы бы видели как пялились на её сиськи молодёж) я та с девушкой был) но всё равно пялился ) потому что хорошие) (с) Browser

Слабая раздача, которую заиграл исключительно из-за колпака на 111. (с) Сатир

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