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Wars of the Wizards 2

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#284
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Scorpiona
Is it possible to officially summarize the results of our group "K"?
Because three players have the same number of points.
I would like to avoid delaying things:smile14:

information

I have updated the group tables.

1. Substitutions:
korvet will replace MuLLIyTa in group A.

2. In group "K", a situation has arisen where three players in 1st-3rd place have the same number of points, and the same Berger score, regardless of the result of the remaining match in the group.

According to the regulations:
If several players have the same number of points, then additional criteria come into effect (in order of priority):
a) Berger coefficient;
b) Head-to-head results;
c) If it is impossible to prioritize based on additional criteria a, b, a tie-breaker match is held on the skirmish m-200 template.

Thus, there is a need for tie-breakers.
Since the tie-breaker is held for three players, to avoid re-matches in case of a 1-1 result, we will add an additional criterion - the difference in the duration of the won and lost matches.
That is, the duration (number of days) of the match in which the player wins is counted as a plus, and the duration of the match in which the player loses is counted as a minus. As a result, the player with the largest negative number will take a higher place (in simple terms, you need to win the match as quickly as possible and lose it for as long as possible).
This criterion applies only in case of a repeated result - 1 win/1 loss for each participant.

Also, with the agreement of the participants, reports on games without an automated reporting system are allowed, i.e., by a regular message in the topic (of course, with all the necessary details).

By mutual agreement with the participants of the tie-breaker games, they will be held on the 6lm10a template, with a deadline for the games until March 6, 2016.

Scorpiona - Toganash
Toganash - HellLighT
HellLighT - Scorpiona

UTC+03:00, icq 593626431