Uran is right.
v/sqrt(2) + o(v)
If the ant moves, the spider should move perpendicularly to the ant's edge.
Added 1 minute ago
Although, no, o(v) doesn't seem to be needed. It's better to return to the bisector if the ant changes direction; it will be easier for the spider, and the path will be shorter compared to the one it traveled while deviating from the bisector. It will gain an advantage because of this.
Added 6 minutes ago
I want to clarify that we have an ideal spider that has instant reaction to changes in the ant's velocity vector