Full random JC

Let's say 77 participants registered, 76 of them found a match, and 1 got a free pass. In the second round, 76/2 + 1 = 39 people will advance. So, does that mean Roger will get a free pass again? Or am I calculating it wrong, Kostya?

Artyom, you're acting like you've never played before. If 77 participants are playing, the bracket will always be in the form of 2^n, i.e., 128 people. This means that in the first round, 26 people will play, and 51 will get a free pass. After the first round, 64 people will remain, and the bracket will proceed smoothly from there.