Six players, seven votes, a double vote for the advisor, the orator stole a zero vote; he can't be there.
Vote breakdown:
Execute ToX -- 6 (Sky, Arandor, Drakkosha, Mortulus, RiMpel2, Warrior777)
Execute Drakkosha -- 1 (Naver Leengard)
Tear apart NNV -- 5 (Ple-Sen, OUGHT, Gur, ToX, WisTrit)
It is known that Naver is a robot. In the "game of killers," there should be one more vote than in the "game of pacifists." There are two robots and an advisor at stake. If the Advisor is a pacifist, then there is +1 vote for the pacifists. If both robots are pacifists, then there are -2 votes for the pacifists. This gives us a breakdown of 6 votes for the killers against 4 votes for the pacifists. Therefore, the advisor MAY not be among the killers.
But yes, it is unlikely - if we assume a random distribution of votes, then the probability of the advisor being a pacifist is 25% (0.5 * 0.5).
In this case, I will indeed remove a vote from RiMpel, but for now, I will refrain from casting it against WisTrit.
Added 3 minutes later
Stop, I forgot that there are not two, but three robots at stake. Then the probability of a pacifist increases to 3/8, but this is still not enough to make decisions based on this theory.
Elizer Yudkovsky, "HP and the Methods of Rationality".
Мой ник транслитерируется по-разному, но я предпочитаю варианты Оот и Ооот.