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Mafia 71. Ancient World

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#324
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Six players, seven votes, a double vote for the advisor, the orator stole a zero vote; he can't be there.
So, let's go over it again. There are 14 votes in the game - 4 + 1 = 11. Revan the robot had a vote stolen. On the first day, there are 11 votes in the game. A majority requires 5 + 1 = 6.
Vote breakdown:
Execute ToX -- 6 (Sky, Arandor, Drakkosha, Mortulus, RiMpel2, Warrior777)
Execute Drakkosha -- 1 (Naver Leengard)
Tear apart NNV -- 5 (Ple-Sen, OUGHT, Gur, ToX, WisTrit)
It is known that Naver is a robot. In the "game of killers," there should be one more vote than in the "game of pacifists." There are two robots and an advisor at stake. If the Advisor is a pacifist, then there is +1 vote for the pacifists. If both robots are pacifists, then there are -2 votes for the pacifists. This gives us a breakdown of 6 votes for the killers against 4 votes for the pacifists. Therefore, the advisor MAY not be among the killers.

But yes, it is unlikely - if we assume a random distribution of votes, then the probability of the advisor being a pacifist is 25% (0.5 * 0.5).

In this case, I will indeed remove a vote from RiMpel, but for now, I will refrain from casting it against WisTrit.

Added 3 minutes later
Stop, I forgot that there are not two, but three robots at stake. Then the probability of a pacifist increases to 3/8, but this is still not enough to make decisions based on this theory.
Batman is a murderer no less than the Joker, for all the lives the Joker took that Batman could've saved by killing him.
Elizer Yudkovsky, "HP and the Methods of Rationality".
Мой ник транслитерируется по-разному, но я предпочитаю варианты Оот и Ооот.