Four people are playing rock-paper-scissors. Like in a playground, everyone shows their choice simultaneously. Therefore, in my opinion, if, as Ples says, the three of them show different choices, it will be an endless game.
Ideally, in any pair, the chances of winning are 50/50.
Therefore, there are two options:
1) Either all four players show a random choice. Then the chance of losing for each is 25%, including the villain.
2) Or the three show the same choice all the time. Then the villain has a 50% chance of losing, and the remaining three have a 50% chance among themselves.
Am I thinking correctly?

В тихой однообразной жизни всегда так бывает: каждый отдельный день бесконечно долог, но месяцы и годы мчатся с непостижимой быстротой.
I wanted to offer you some flowers, but a crown would suit a princess like you much better
Смысл жизни в том, что жизнь на тебе не заканчивается