OFB-12

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Georg_

Redwhait 140 - 4*3 + 5*0.5 = 130.5
Georg_ 136 - 3*3 + 6*0.5 = 130

If 0.5 is changed to 1, it will be 133 for both. Or am I misunderstanding something?

Dirty_Player

Let's try.
Redwhait:
1) Sir Davos has 15 points (5 wins), including 2 free wins in rounds 4 and 9. The program doesn't count them, but considers them as two draws with +0.5. Total: 9+0.5+0.5 = 10
2) Ihromant, the same: 15 (9+0.5+0.5 = 10)
3) YaR 12 has one free loss in the last round, but it also counts as +0.5 (12+0.5 = 12.5)
4) herolwy 22, all games played normally, so +22 in the coefficient
5) kamukad3e 19, all games played
6) Roger-ua 12, all games played
7) sonic111 15, all games played
8) SECTOR767 15, all games played
9) HellLighT 15, all games played
Total: 10+10+12.5+22+19+12+15+15+15 = 130.5

Indeed, judging by the calculated coefficient for Redwhait, and if Georg didn't make a mistake when calculating his coefficient, then if both have 0.5 replaced with 1 (as it should be in the 3-1-0 system), the number of points will be equal.
Ideally, for all 6 players with 18 points, such a detailed calculation should be done in the 3-1-0 system. Otherwise, these are unconfirmed figures (some unspecified program, and also results from two different versions are taken into account), contradicting the regulations (there are no 0.5 values there).

Ah, it was already briefly described for 0.5:

Dirty_Player

Dima Surmay 138 - 1*3 + 10*0.5 = 140
Yostaris 123 - 0 + 17*0.5 = 131.5
Redwhait 140 - 4*3 + 5*0.5 = 130.5
Georg_ 136 - 3*3 + 6*0.5 = 130
Amiloo 108 - 1*3 + 16*0.5 = 113

Changing 0.5 to 1:
Dima Surmay 138 - 1*3 + 10*1 = 145
Yostaris 123 - 0 + 17*1 = 140
Redwhait 140 - 4*3 + 5*1 = 133
Georg_ 136 - 3*3 + 6*1 = 133
Amiloo 108 - 1*3 + 16*1 = 121

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