OFB-12

As I understand it, in the first case, the system gives him +18 and +0.5 = 18.5 (I don't know why you have -3 in your calculation)

But you calculate free wins in the same way, right? A free win is calculated as a draw with oneself. That is, the player's own score is added to the Buchholz score, but taking into account that this game was played as a draw. Accordingly, in the total score, it is not 18, but 18 - 3 + 0.5 (since for this game he does not receive 3 points for a win, but receives 0.5 for a draw)

And I am more concerned about the answer to my previous post, where, taking into account that a draw should give 1 instead of 0.5 (which looks more logical and reasonable), Redwait and I have an equal Buchholz score.