OFB-12

Could you provide an example using Redwhait to explain how the Buchholz coefficient is calculated manually for those who are not familiar with it? If I'm not mistaken, Redwhait doesn't have any free wins or free losses.

It takes into account the free wins and free losses not only of the player himself, but also of those he played against.

Added 1 hour 8 minutes ago

In the old version, the program would sometimes break the pairings and assign a draw against himself when calculating the coefficient. At the same time, the players could meet each other again. In the latest version, the program doesn't break the pairings, but assigns a conditional draw to the players and calculates based on that.

Where did the difference of 7.5 points come from? (132.5 and 125)
In the first situation, he receives +15.5 in the Buchholz coefficient for this game (a draw with himself and, accordingly, the sum of his own points, but taking into account that the game was a draw: 18-3+0.5)

and in the second, +12.5 (a draw with Dusto, the sum of Dusto's points, taking into account that the game was a draw: 12+0.5)

Added 5 minutes ago
In general, there is no clear explanation of how the Buchholz coefficient should be calculated correctly, there is no understanding of how the program calculates it, and accordingly, it is impossible to verify the data it provides, to check whether an error was made when entering the data into it. Accordingly, there are all grounds for applying a clause from the regulations:

In the event of a tie in points, the following additional criteria apply in order of priority:
1) Buchholz coefficient;
2) Number of wins;
3) Head-to-head result;
If the places cannot be determined between the participants who have the opportunity to reach the final stage of the tournament, tie-breaks will be held.