OFB-12

But why bother figuring out how the program calculates it (it would be good for the future, of course)? According to the regulations, there can't be any 0.5:

You can just calculate the total score, but the program doesn't give these bonuses for no reason. And why is that? For example, in the first round, Amilu played against an opponent with the nickname Johnny the bony, who lost two games and left the tournament without finishing it. Therefore, his coefficient is 0! Which automatically eliminates him from the candidates to advance, in almost any distribution. Is he to blame for encountering such an opponent in the first round? I don't think so. It is precisely because of such situations that the system gives additional points for unplayed games. However, other questions arise. Why +0.5? And why do different versions of the program calculate differently for Tvarina? Who to believe? :smile39:

and the coefficient provided by the program is decisive.

I recommend including exactly this wording in the next official rules. What the program shows should be considered the truth. What to do now - we will think about it.

Added 3 minutes ago

Perhaps the confusion arose due to this nuance:

"Appendix to the FIDE Tournament Rules
Rules for the application of additional indicators
Approved by the General Assembly in 1998
1. Accounting for unplayed games
To eliminate the undesirable influence of unplayed games on the distribution of places, these games should be counted as follows.
Regardless of the result of the unplayed game (win in the case when the player receives a point due to being "exempt from play," win or loss by default, or the game was not played because the player withdrew or was absent for one or more rounds), this result should be considered when determining the additional indicator as a draw of the player against himself."

Yes, that's exactly what I was talking about. The problem is that I completely forgot about the phrase highlighted in bold. Then I will try to figure out Tvarina's coefficient again.

That is, when calculating the Buchholz score, the program treats technical wins or unplayed games of withdrawn players as draws with oneself. However, it is still not clear where these 0.5 come from...

I only have one hypothesis about +0.5. The program was originally designed for a 1-0.5-0 point system, and a draw gives +0.5. In theory, with a 3-1-0 system, it should give +1, but it still gives +0.5. Which looks like a clear bug.